The de-Broglie wavelength of the electron in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Bohr's quantization condition,the angular momentum of an electron in an orbit is given by:$mvr = \frac{nh}{2\pi}$Rearranging this,we

Vedclass · Accepted Answer

$3.33$

Vedclass · Answer

(B) According to Bohr's quantization condition,the angular momentum of an electron in an orbit is given by:$mvr = \frac{nh}{2\pi}$Rearranging this,we get:$\frac{h}{mv} = \frac{2\pi r}{n}$ .......... $(i)$The de-Broglie wavelength $\lambda$ of an electron is given by:$\lambda = \frac{h}{mv}$ .......... $(ii)$Comparing equations $(i)$ and $(ii)$,we get:$\lambda = \frac{2\pi r}{n}$For the ground state (first orbit) of the hydrogen atom,$n = 1$ and $r = 0.53 \ \mathring{A}$.Substituting these values:$\lambda = \frac{2 	imes 3.1416 	imes 0.53}{1} \ \mathring{A} \approx 3.33 \ \mathring{A}$.

The de-Broglie wavelength of the electron in the ground state of the hydrogen atom is . . . . . . $\mathring{A}$ (radius of the first orbit of hydrogen atom $= 0.53 \ \mathring{A}$).

Similar Questions

If there were no gravity,which of the following will not be there for a fluid?

Consider a circle with its centre lying on the focus of the parabola $y^2 = 2px$ such that it touches the directrix of the parabola. Then a point of intersection of the circle and the parabola is:

If $\frac{x^2+x+1}{x^2+2x+1} = A + \frac{B}{x+1} + \frac{C}{(x+1)^2}$,then $A-B$ is equal to

Which of the following metal carbonates decomposes upon heating?

Which of the following can show geometrical isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module