Medium
The decomposition of dimethyl ether leads to the formation of $CH_4$,$H_2$ and $CO$ and the reaction rate is given by
Rate $= k [CH_3OCH_3]^{3/2}$
The rate of reaction is followed by increase in pressure in a closed vessel,so the rate can also be expressed in terms of the partial pressure of dimethyl ether,i.e.
Rate $= k (p_{CH_3OCH_3})^{3/2}$
If the pressure is measured in $bar$ and time in $minutes$,then what are the units of rate and rate constants?
Rate $= k [CH_3OCH_3]^{3/2}$
The rate of reaction is followed by increase in pressure in a closed vessel,so the rate can also be expressed in terms of the partial pressure of dimethyl ether,i.e.
Rate $= k (p_{CH_3OCH_3})^{3/2}$
If the pressure is measured in $bar$ and time in $minutes$,then what are the units of rate and rate constants?
(N/A) If pressure is measured in $bar$ and time in $minutes$,then:
Unit of rate $= bar \ min^{-1}$
Rate $= k (p_{CH_3OCH_3})^{3/2}$
$\Rightarrow k = \frac{Rate}{(p_{CH_3OCH_3})^{3/2}}$
Therefore,the unit of rate constant $(k) = \frac{bar \ min^{-1}}{bar^{3/2}} = bar^{-1/2} \ min^{-1}$
Unit of rate $= bar \ min^{-1}$
Rate $= k (p_{CH_3OCH_3})^{3/2}$
$\Rightarrow k = \frac{Rate}{(p_{CH_3OCH_3})^{3/2}}$
Therefore,the unit of rate constant $(k) = \frac{bar \ min^{-1}}{bar^{3/2}} = bar^{-1/2} \ min^{-1}$
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