The decreasing order of the number of ionisab | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The number of ionisable hydrogen atoms in an oxoacid of phosphorus is equal to the number of $P-OH$ bonds present in the molecule.$1$. $H_3PO_4$ (

Vedclass · Accepted Answer

$IV > I > II > III$

Vedclass · Answer

(C) The number of ionisable hydrogen atoms in an oxoacid of phosphorus is equal to the number of $P-OH$ bonds present in the molecule.$1$. $H_3PO_4$ (Orthophosphoric acid): Contains $3$ $P-OH$ bonds, so it has $3$ ionisable hydrogen atoms.$2$. $H_3PO_3$ (Phosphorous acid): Contains $2$ $P-OH$ bonds, so it has $2$ ionisable hydrogen atoms.$3$. $H_3PO_2$ (Hypophosphorous acid): Contains $1$ $P-OH$ bond, so it has $1$ ionisable hydrogen atom.$4$. $H_4P_2O_6$ (Hypophosphoric acid): Contains $4$ $P-OH$ bonds, so it has $4$ ionisable hydrogen atoms.Comparing the number of ionisable hydrogen atoms:$IV (4) > I (3) > II (2) > III (1)$Therefore, the decreasing order is $IV > I > II > III$.

The decreasing order of the number of ionisable hydrogen atoms in the following molecules is:
$I$. $H_3PO_4$
$II$. $H_3PO_3$
$III$. $H_3PO_2$
$IV$. $H_4P_2O_6$

Similar Questions

The $+1$ oxidation state in group $13$ and $+2$ oxidation state in group $14$ become more stable with increasing atomic number. Explain.

Metaphosphoric acid has the formula

The oxidation number of phosphorus varies from

The acidic character of the group-$15$ elements' oxides in increasing order is:

The treatment of galena $(PbS)$ with $HNO_3$ produces a gas that is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The decreasing order of the number of ionisable hydrogen atoms in the following molecules is:$I$. $H_3PO_4$$II$. $H_3PO_3$$III$. $H_3PO_2$$IV$. $H_4P_2O_6$