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(D) The degree of a differential equation is defined only when it is a polynomial equation in terms of its derivatives. In the given equation $\left(\

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Not defined

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(D) The degree of a differential equation is defined only when it is a polynomial equation in terms of its derivatives. In the given equation $\left(\frac{d^2 y}{d x^2}\right)^5+\left(\frac{d y}{d x}\right)^2+\cos \left(\frac{d y}{d x}\right)+1=0$,the term $\cos \left(\frac{d y}{d x}\right)$ involves a transcendental function of the derivative $\frac{d y}{d x}$. Because this term cannot be expressed as a polynomial in terms of the derivatives,the degree of the differential equation is not defined. Therefore,the correct option is $D$.

The degree of the differential equation $\left(\frac{d^2 y}{d x^2}\right)^5+\left(\frac{d y}{d x}\right)^2+\cos \left(\frac{d y}{d x}\right)+1=0$ is . . . . . . .

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