The degree of the differential equation left( | vedclass

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Question

(B) The given differential equation is $\left(\frac{d^{2} y}{d x^{2}}\right)^{3}+\left(\frac{d y}{d x}\right)^{2}+\sin \left(\frac{d y}{d x}\right)+1=

Vedclass · Accepted Answer

not defined

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(B) The given differential equation is $\left(\frac{d^{2} y}{d x^{2}}\right)^{3}+\left(\frac{d y}{d x}\right)^{2}+\sin \left(\frac{d y}{d x}\right)+1=0$. The degree of a differential equation is defined only when it can be expressed as a polynomial in its derivatives. In this equation,the term $\sin \left(\frac{d y}{d x}\right)$ involves a derivative as an argument of a transcendental function,which prevents the equation from being a polynomial in its derivatives. Therefore,the degree of this differential equation is not defined. Hence,the correct answer is $B$.

The degree of the differential equation $\left(\frac{d^{2} y}{d x^{2}}\right)^{3}+\left(\frac{d y}{d x}\right)^{2}+\sin \left(\frac{d y}{d x}\right)+1=0$ is

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