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(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the density $(d)$ of the gas: $

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$4 : 1$

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(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the density $(d)$ of the gas: $r \propto \frac{1}{\sqrt{d}}$.Given the ratio of densities: $\frac{d_1}{d_2} = \frac{1}{16}$.The ratio of their rates of diffusion is: $\frac{r_1}{r_2} = \sqrt{\frac{d_2}{d_1}} = \sqrt{\frac{16}{1}} = \frac{4}{1}$.Thus,the ratio is $4 : 1$.

The densities of two gases are in the ratio of $1 : 16$. The ratio of their rates of diffusion is

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