The density of 2 M aqueous solution of NaOH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $2 \ M$ solution of $NaOH$ means $2 \ mol$ of $NaOH$ is present in $1 \ L$ of solution.Density of solution $= 1.28 \ g \ mL^{-1}$.Mass of solution

Vedclass · Accepted Answer

$1.67$

Vedclass · Answer

(C) $2 \ M$ solution of $NaOH$ means $2 \ mol$ of $NaOH$ is present in $1 \ L$ of solution.Density of solution $= 1.28 \ g \ mL^{-1}$.Mass of solution $=$ Volume $	imes$ Density $= 1000 \ mL 	imes 1.28 \ g \ mL^{-1} = 1280 \ g$.Mass of solute $(NaOH)$ $= 2 \ mol 	imes 40 \ g \ mol^{-1} = 80 \ g$.Mass of solvent (water) $=$ Mass of solution $-$ Mass of solute $= 1280 \ g - 80 \ g = 1200 \ g = 1.2 \ kg$.Molality $(m) = \frac{	ext{moles of solute}}{	ext{mass of solvent in kg}} = \frac{2 \ mol}{1.2 \ kg} = 1.67 \ m$.

The density of $2 \ M$ aqueous solution of $NaOH$ is $1.28 \ g \ cm^{-3}.$ The molality of the solution is $... \ m$ [Given that molecular mass of $NaOH = 40 \ g \ mol^{-1}$]

Similar Questions

$5 \, L$ of a gaseous mixture of ethane and propane are burnt to produce total $11 \, L$ of $CO_2$. Volume percent of $C_2H_6$ in the initial mixture is

What is the percentage atom economy during the conversion of reactant to product if the formula weight of reactants is $246 \ u$ and that of the product is $123 \ u$ (in $\%$)?

What will be the normality of a solution containing $4.9 \ g$ of $H_3PO_4$ dissolved in $500 \ mL$ water (in $N$)?

What is the value of percent atom economy if the molar mass of reactants is $36 \ u$ and the mass of the desired product is $27 \ u$ (in $\%$)?

To obtain the maximum mass of $NO_2$ from a given mass of a mixture of $NH_3$ and $O_2$,the ratio of the mass of $NH_3$ to $O_2$ should be based on the reaction: $NH_3 + O_2 \longrightarrow NO_2 + H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module