The density of a metal at normal pressure $P$ is $\varrho$. When it is subjected to an excess pressure $p$,the density becomes $\varrho^{\prime}$. If $K$ is the bulk modulus of the metal,then the ratio $\frac{\varrho^{\prime}}{\varrho}$ is

Consider a fluid in a container. Let the density of the fluid at the surface and at depth $H$ be $\rho_0$ and $\rho$ respectively. The bulk modulus of the fluid is $B_0$. If $\rho = \frac{\rho_0}{1 - \frac{\rho g H}{B_0}}$, find the constant $\alpha$ in the expression $\rho = \frac{\rho_0}{1 + \alpha \rho g H}$ (Assume $\frac{\rho - \rho_0}{\rho_0} \ll 1$).

When a sphere is taken to the bottom of a sea of depth $1 \ km$,it contracts in volume by $0.01 \%$. The bulk modulus of the material of the sphere is (Acceleration due to gravity $= 10 \ m \ s^{-2}$,density of sea water $= 10^3 \ kg \ m^{-3}$)

What is the relationship between the isothermal bulk modulus $E_\theta$ and the adiabatic bulk modulus $E_\phi$? (where $\gamma = C_p/C_v$)

Among the three states of matter (solid,liquid,and gas),which elastic coefficient is applicable to all of them?

$A$ sphere contracts in volume by $0.01 \%$ when taken to the bottom of a sea $1 \,km$ deep. Find the Bulk modulus of the material of the sphere in $N/m^2$.