The dibromo compound [P] (molecular formula : | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1$. The compound $[P]$ is $1,1-dibromo-1-(4-methylphenyl)methane$ (also known as $4-methylbenzal$ bromide, bu

Vedclass · Accepted Answer

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. The compound $[P]$ is $1,1-dibromo-1-(4-methylphenyl)methane$ (also known as $4-methylbenzal$ bromide, but with the formula $C_9H_{10}Br_2$, it is $1-(1,1-dibromoethyl)-4-methylbenzene$ or similar gem-dibromide structure).$2$. Treatment of $[P]$ with excess $NaNH_2$ followed by $HCl$ leads to dehydrohalogenation, forming the terminal alkyne $[Q]$, which is $1-ethynyl-4-methylbenzene$ $(p-methylphenylacetylene)$.$3$. Hydration of the alkyne $[Q]$ with $HgSO_4$ and $dil. H_2SO_4$ (Kucherov reaction) yields the ketone $[R]$, which is $4-methylacetophenone$.$4$. $4-methylacetophenone$ contains a $CH_3CO-$ group, thus it gives a positive Iodoform test. It is a ketone, so it gives a negative Tollen's test.$5$. Therefore, $[P]$ is $1,1-dibromoethyl-4-methylbenzene$ (represented by option $C$).

Similar Questions

The major product of the given reaction is:

The number of sigma and pi bonds in $but-1-ene-3-yne$ are

The product $(A)$ is

Which of the following most accurately describes the first step in the reaction of hydrogen chloride with $1$-butene?

Identify the final product $(B)$ in the following reaction sequence:
$1\text{-bromo-}2\text{-methylcyclobutane}$ $\xrightarrow{\text{alc. KOH}} A$ $\xrightarrow{\text{ozonolysis}} B$

Vedclass Test Series

Exam Paper Generator

Online Exam Module