The difference between bond orders of CO and | vedclass

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(A) The total number of electrons in $CO$ is $6 + 8 = 14$. According to Molecular Orbital Theory,the bond order of a $14$-electron species is $\frac{1

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(A) The total number of electrons in $CO$ is $6 + 8 = 14$. According to Molecular Orbital Theory,the bond order of a $14$-electron species is $\frac{10-4}{2} = 3$.The total number of electrons in $NO^{\oplus}$ is $7 + 8 - 1 = 14$. Similarly,the bond order of $NO^{\oplus}$ is $\frac{10-4}{2} = 3$.The difference between the bond orders is $|3 - 3| = 0$.Given that the difference is $\frac{x}{2}$,we have $\frac{x}{2} = 0$,which implies $x = 0$.

The difference between bond orders of $CO$ and $NO^{\oplus}$ is $\frac{x}{2}$ where $x = .....$
(Round off to the Nearest Integer)

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The difference between bond orders of $CO$ and $NO^{\oplus}$ is $\frac{x}{2}$ where $x = .....$(Round off to the Nearest Integer)