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(B) Simple Interest $(SI)$ for $1$ year at $10 \%$ per annum on ₹ $600$ is calculated as:$SI = \frac{P 	imes R 	imes T}{100} = \frac{600 	imes 10 \

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$1.5$

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(B) Simple Interest $(SI)$ for $1$ year at $10 \%$ per annum on ₹ $600$ is calculated as:$SI = \frac{P 	imes R 	imes T}{100} = \frac{600 	imes 10 	imes 1}{100} = ₹ 60$.For Compound Interest $(CI)$ reckoned half-yearly,the rate $R$ becomes $10/2 = 5 \%$ per half-year and the time $T$ becomes $1 	imes 2 = 2$ half-years.$CI = P \left[ (1 + \frac{R}{100})^n - 1 ight] = 600 \left[ (1 + \frac{5}{100})^2 - 1 ight]$$CI = 600 \left[ (1.05)^2 - 1 ight] = 600 \left[ 1.1025 - 1 ight] = 600 	imes 0.1025 = ₹ 61.50$.Difference $= CI - SI = ₹ 61.50 - ₹ 60 = ₹ 1.50$.

The difference between the simple interest and the compound interest (in ₹) on ₹ $600$ for $1$ year at $10 \%$ per annum,reckoned half-yearly is

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