The dimensional formula $[ML^0T^{-3}]$ is more closely associated with

The position of a particle at time $t$ is given by the equation $x(t) = \frac{v_0}{A}(1 - e^{-At})$, where $v_0$ is a constant and $A > 0$. The dimensions of $v_0$ and $A$ respectively are:

The expression $[M{L^2}{T^{ - 2}}]$ represents

The physical quantity that has the same dimensional formula as pressure is:

Time $(T)$,velocity $(C)$,and angular momentum $(h)$ are chosen as fundamental quantities instead of mass,length,and time. In terms of these,the dimensions of mass would be

In $SI$ units, the dimensions of $\sqrt {\frac{\varepsilon_0}{\mu_0}}$ are: