The dipole moment of o-,p- and m-dichlorobenz | vedclass

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(D) The dipole moment of $p-$dichlorobenzene is $0$ because of its symmetrical structure,where the bond dipoles cancel each other out.In $o-$dichlorob

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$o > m > p$

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(D) The dipole moment of $p-$dichlorobenzene is $0$ because of its symmetrical structure,where the bond dipoles cancel each other out.In $o-$dichlorobenzene,the angle between the $C-Cl$ bonds is $60^\circ$,resulting in a large resultant dipole moment.In $m-$dichlorobenzene,the angle between the $C-Cl$ bonds is $120^\circ$,which results in a smaller resultant dipole moment compared to the $o-$isomer.Therefore,the order of decreasing dipole moment is: $o-dichlorobenzene > m-dichlorobenzene > p-dichlorobenzene$.

The dipole moment of $o-$,$p-$ and $m-$dichlorobenzene will be in the order:

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