The dipole moment of $H_2O_2$ is more than that of $H_2O$,but $H_2O_2$ is not a good solvent because:
- AIt has a very high dielectric constant so that ionic compounds cannot be dissolved in it.
- BIt does not act as an oxidising agent.
- CIt acts as a reducing agent.
- DIt dissociates easily and acts as an oxidising agent in chemical reactions.
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Similar Questions
$A$ : The $O-O$ bond length in $H_2O_2$ is smaller than that in $O_2F_2$.
$R$ : $H_2O_2$ is an ionic compound.
$R$ : $H_2O_2$ is an ionic compound.
Difficult
View Solution$H_2O_2$ can be used as:
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View SolutionStrength of a $H_2O_2$ solution is labelled as $1.79 \, N$. Its strength can also be expressed as closest to $... \, \text{volume}$.
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View Solution$6.8 \, g$ of $H_2O_2$ is dissolved in $0.2 \, L$ of solution. Then the solution will be labelled as ............. $V$ volume strength.
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View SolutionWhich method is currently used for the industrial production of $H_2O_2$?
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