The direction of the magnetic force on the el | vedclass

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(A) The magnetic field produced by the current-carrying wire at the position of the electron is directed into the plane of the paper,which is in the $

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$y$-axis

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(A) The magnetic field produced by the current-carrying wire at the position of the electron is directed into the plane of the paper,which is in the $-\hat{k}$ direction.The velocity of the electron is directed along the negative $x$-axis,so $\vec{v} = -v\hat{i}$.The magnetic force on a charge $q$ is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.For an electron,$q = -e$. Substituting the values:$\vec{F} = -e [(-v\hat{i}) 	imes (-B\hat{k})]$$\vec{F} = -e [vB(\hat{i} 	imes \hat{k})]$Since $\hat{i} 	imes \hat{k} = -\hat{j}$,we get:$\vec{F} = -e [vB(-\hat{j})] = evB\hat{j}$.Thus,the direction of the magnetic force is along the positive $y$-axis.

The direction of the magnetic force on the electron as shown in the diagram is along:

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