(D) The given reaction $_{11}Na^{24} \to _{12}Mg^{24} + _{-1}e^0$ represents $\beta$-decay.In $\beta$-decay,a neutron is converted into a proton,which

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(D) The given reaction $_{11}Na^{24} \to _{12}Mg^{24} + _{-1}e^0$ represents $\beta$-decay.In $\beta$-decay,a neutron is converted into a proton,which increases the atomic number by $1$ while the mass number remains constant.This process leads to the emission of $\beta$-radiation,helps in achieving a more stable nuclide,and results in a decrease in the neutron $:$ proton ratio.

Class 12 Chemistry Nuclear Chemistry Radioactivity and a,b and g rays

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The disintegration of an isotope of sodium,$_{11}Na^{24} \to _{12}Mg^{24} + _{-1}e^0$,shown is due to

A
The emission of $\beta$-radiation
B
The formation of a stable nuclide
C
The fall in the neutron $:$ proton ratio
D
All of the above

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Nuclear Chemistry

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Radioactivity and a,b and g rays

$A$ device used for the measurement of radioactivity is

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$_{72}^{180}X$ $\xrightarrow{2\alpha}$ $\xrightarrow{\beta}$ $\xrightarrow{\gamma} _{Z}^{A}X'$. The values of $Z$ and $A$ are:

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Which of the following processes does not occur via $\alpha$-decay?

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The radiations from a naturally occurring radio element,as seen after deflection in a magnetic field in one direction,are

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After losing a number of $\alpha$ and $\beta$ particles,$_{92}U^{238}$ changed to $_{82}Pb^{206}$. The total number of particles lost in this process is

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The disintegration of an isotope of sodium,$_{11}Na^{24} \to _{12}Mg^{24} + _{-1}e^0$,shown is due to

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$A$ device used for the measurement of radioactivity is

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