The displacement of a body when it covers a d | vedclass

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(B) The given situation is shown in the figure. When the body covers a distance of $C / 4$,where $C$ is the circumference,it moves from point $A$ to p

Vedclass · Accepted Answer

$r \sqrt{2}$

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(B) The given situation is shown in the figure. When the body covers a distance of $C / 4$,where $C$ is the circumference,it moves from point $A$ to point $B$ along the circular path.Since the distance covered is one-fourth of the circumference,the angle subtended at the center $O$ is $90^{\circ}$.Thus,$	riangle OAB$ is a right-angled triangle with $OA = OB = r$.The displacement is the straight-line distance between the initial position $A$ and the final position $B$.Using the Pythagorean theorem:$	ext{Displacement} = AB = \sqrt{OA^2 + OB^2}$$	ext{Displacement} = \sqrt{r^2 + r^2} = \sqrt{2r^2} = r \sqrt{2}$

The displacement of a body when it covers a distance of $C / 4$ (where,$C$ is circumference) along the circumference of a circle of radius $r$ with a uniform speed $u$ is

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