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(C) The displacement of the particle is given by the equation $y = a + bt + ct^2 - dt^4$.To find the velocity $v$,we differentiate the displacement $y

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$b, 2c$

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(C) The displacement of the particle is given by the equation $y = a + bt + ct^2 - dt^4$.To find the velocity $v$,we differentiate the displacement $y$ with respect to time $t$:$v = \frac{dy}{dt} = \frac{d}{dt}(a + bt + ct^2 - dt^4) = b + 2ct - 4dt^3$.To find the acceleration $a_{acc}$,we differentiate the velocity $v$ with respect to time $t$:$a_{acc} = \frac{dv}{dt} = \frac{d}{dt}(b + 2ct - 4dt^3) = 2c - 12dt^2$.At the initial time $t = 0$:Initial velocity $v_{initial} = b + 2c(0) - 4d(0)^3 = b$.Initial acceleration $a_{initial} = 2c - 12d(0)^2 = 2c$.Therefore,the initial velocity is $b$ and the initial acceleration is $2c$.

The displacement of a particle is given by $y = a + bt + ct^2 - dt^4$. The initial velocity and acceleration are respectively

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