The displacements of two particles executing $S.H.M.$ on the same line are given as $y_1 = a \sin \left(\frac{\pi}{2} t + \phi\right)$ and $y_2 = b \sin \left(\frac{2 \pi}{3} t + \phi\right)$. The phase difference between them at $t = 1 \, s$ is .........
- A$\pi$
- B$\frac{\pi}{2}$
- C$\frac{\pi}{4}$
- D$\frac{\pi}{6}$
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