The dissociation constants of two acids HY an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relative strength of two acids is given by the ratio of the square roots of their dissociation constants: $	ext{Relative strength} = \sqrt{\f

Vedclass · Accepted Answer

$4 : 1$

Vedclass · Answer

(B) The relative strength of two acids is given by the ratio of the square roots of their dissociation constants: $	ext{Relative strength} = \sqrt{\frac{K_{a1}}{K_{a2}}}$Given $K_{a1} = 2.88 	imes 10^{-4}$ and $K_{a2} = 1.8 	imes 10^{-5}$.$	ext{Relative strength} = \sqrt{\frac{2.88 	imes 10^{-4}}{1.8 	imes 10^{-5}}} = \sqrt{\frac{28.8 	imes 10^{-5}}{1.8 	imes 10^{-5}}} = \sqrt{16} = 4$.Thus,the ratio is $4 : 1$.

The dissociation constants of two acids $HY$ and $HZ$ are $2.88 \times 10^{-4}$ and $1.8 \times 10^{-5}$ respectively. The relative strength of the acids will be :-

Similar Questions

Arrange $NH_4^+$,$H_2O$,$H_3O^+$,$HF$,and $OH^-$ in increasing order of their acidic strength.

The process $HCN \to H^+ + CN^-$ should be ...........

Complete the following Acid-Base reactions and identify each reactant as an Acid or a Base:
$(i)$ $CH_3NH_2 + H_2O$
$(ii)$ $CO_2 + H_2O$
$(iii)$ $H_2PO_4^- + CO_3^{2-}$
$(iv)$ $NH_2NH_2 + H_2O$
$(v)$ $C_6H_6 + NO_2^+$
$(vi)$ $C_6H_6 + NH_2^-$

Four species are listed below:
$i. \, HCO_3^-$
$ii. \, H_3O^{+}$
$iii. \, HSO_4^-$
$iv. \, HSO_3F$
Which one of the following is the correct sequence of their acid strength?

Would gaseous $HCl$ be considered as an Arrhenius acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module