The dissolution of Al(OH)_3 by a solution of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $Al(OH)_3$ is an amphoteric hydroxide that dissolves in a strong base like $NaOH$ to form a soluble complex.In aqueous solution,the aluminum ion m

Vedclass · Accepted Answer

$[Al(H_2O)_2(OH)_4]^-$

Vedclass · Answer

(C) $Al(OH)_3$ is an amphoteric hydroxide that dissolves in a strong base like $NaOH$ to form a soluble complex.In aqueous solution,the aluminum ion maintains its coordination number of $6$.Therefore,the reaction is: $Al(OH)_3(s) + OH^-(aq) + 2H_2O(l) 	o [Al(OH)_4(H_2O)_2]^-(aq)$.Thus,the correct species formed is $[Al(H_2O)_2(OH)_4]^-$,which is option $C$.

The dissolution of $Al(OH)_3$ by a solution of $NaOH$ results in the formation of

Similar Questions

Basicity of $H_3BO_3$ is :

The incorrect statement regarding the above reactions is:
$Al \xrightarrow{HCl(aq.)} 'X' + \text{Gas } 'P'$
$Al \xrightarrow{NaOH(aq.) + H_2O} 'Y' + \text{Gas } 'Q'$

Identify the reaction in which diborane is produced on an industrial scale.

Explain what happens when boric acid is heated.

The correct statement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module