The distance between (7, 5) and (2, 5) is.... | vedclass

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(B) To find the distance between two points $(x_1, y_1)$ and $(x_2, y_2)$,we use the distance formula:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$Here,$

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$5$

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(B) To find the distance between two points $(x_1, y_1)$ and $(x_2, y_2)$,we use the distance formula:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$Here,$(x_1, y_1) = (7, 5)$ and $(x_2, y_2) = (2, 5)$.Substituting the values into the formula:$d = \sqrt{(2 - 7)^2 + (5 - 5)^2}$$d = \sqrt{(-5)^2 + (0)^2}$$d = \sqrt{25 + 0}$$d = \sqrt{25}$$d = 5$Therefore,the distance between the two points is $5$ units.

The distance between $(7, 5)$ and $(2, 5)$ is........

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