The distance between places A and B is 999 te | vedclass

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(A) Step $1$: Calculate the travel time without stops.$	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}} = \frac{999}{55.5} = 18 	ext{ hours}$.Step

Vedclass · Accepted Answer

$1:20$

Vedclass · Answer

(A) Step $1$: Calculate the travel time without stops.$	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}} = \frac{999}{55.5} = 18 	ext{ hours}$.Step $2$: Add the duration of the stops.$	ext{Total time} = 18 	ext{ hours} + 1 	ext{ hour } 20 	ext{ minutes} = 19 	ext{ hours } 20 	ext{ minutes}$.Step $3$: Calculate the arrival time.The train starts at $6:00 	ext{ am}$. Adding $19 	ext{ hours } 20 	ext{ minutes}$ to $6:00 	ext{ am}$:$6:00 	ext{ am} + 12 	ext{ hours} = 6:00 	ext{ pm}$.Remaining time to add: $19 	ext{ hours } 20 	ext{ minutes} - 12 	ext{ hours} = 7 	ext{ hours } 20 	ext{ minutes}$.$6:00 	ext{ pm} + 7 	ext{ hours } 20 	ext{ minutes} = 1:20 	ext{ am}$ (next day).Note: The question asks for the time in $	ext{pm}$,but based on the calculation,the arrival is at $1:20 	ext{ am}$. Given the options,$1:20$ is the correct numerical value.

The distance between places $A$ and $B$ is $999 \text{ km}$. An express train leaves place $A$ at $6:00 \text{ am}$ and runs at a speed of $55.5 \text{ km/h}$. The train stops on the way for $1 \text{ hour } 20 \text{ minutes}$. At what time does it reach place $B$ (in $\text{pm}$)?

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