(C) The given equation is $x^2+2 \sqrt{2} xy+2y^2+4x+4 \sqrt{2}y+1=0$. Comparing this with the general equation $ax^2+2hxy+by^2+2gx+2fy+c=0$,we get $a

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(C) The given equation is $x^2+2 \sqrt{2} xy+2y^2+4x+4 \sqrt{2}y+1=0$. Comparing this with the general equation $ax^2+2hxy+by^2+2gx+2fy+c=0$,we get $a=1$,$h=\sqrt{2}$,$b=2$,$g=2$,$f=2 \sqrt{2}$,and $c=1$. For parallel lines,the distance $d$ is given by the formula $d=2 \sqrt{\frac{g^2-ac}{a(a+b)}}$. Substituting the values: $d=2 \sqrt{\frac{2^2-(1)(1)}{1(1+2)}}$. $d=2 \sqrt{\frac{4-1}{3}} = 2 \sqrt{\frac{3}{3}} = 2 \sqrt{1} = 2$.

Class 11 Mathematics Pair of straight lines Equation of lines joining the origin to the point of intersection of a curve and a line and Distance between the pair of lines

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The distance between the pair of lines $x^2+2 \sqrt{2} xy+2y^2+4x+4 \sqrt{2}y+1=0$ is

AP EAMCET 2019 All AP EAMCET

A
$4 \sqrt{2}$
B
$2 \sqrt{2}$
C
$2$
D
$6 \sqrt{2}$

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Pair of straight lines

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Equation of lines joining the origin to the point of intersection of a curve and a line and Distance between the pair of lines

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The distance between the pair of lines $x^2+2 \sqrt{2} xy+2y^2+4x+4 \sqrt{2}y+1=0$ is

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