The distance between the plates of a parallel | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When a dielectric slab is introduced into a capacitor after disconnecting the battery,the charge $(Q)$ on the plates remains constant.Initial capa

Vedclass · Accepted Answer

The $P.D.$ across the capacitor will be $45\,V$

Vedclass · Answer

(D) When a dielectric slab is introduced into a capacitor after disconnecting the battery,the charge $(Q)$ on the plates remains constant.Initial capacitance $C_0 = \frac{\varepsilon_0 A}{d}$.Initial potential difference $V_0 = 120\,V$.When the dielectric slab of thickness $t = 6\,mm$ and dielectric constant $K = 6$ is inserted into the gap $d = 8\,mm$,the new capacitance $C'$ is given by $C' = \frac{\varepsilon_0 A}{d - t + \frac{t}{K}}$.Since the charge $Q$ is constant,$Q = C_0 V_0 = C' V'$,where $V'$ is the new potential difference.Therefore,$V' = V_0 	imes \frac{C_0}{C'} = V_0 	imes \frac{d - t + \frac{t}{K}}{d}$.Substituting the values: $V' = 120 	imes \frac{8 - 6 + \frac{6}{6}}{8} = 120 	imes \frac{2 + 1}{8} = 120 	imes \frac{3}{8} = 15 	imes 3 = 45\,V$.

The distance between the plates of a parallel plate capacitor is $8\,mm$ and the potential difference $(P.D.)$ is $120\,V$. If a $6\,mm$ thick slab of dielectric constant $K = 6$ is introduced between its plates,then:

Similar Questions

Half of the space between the plates of a parallel-plate capacitor is filled with a dielectric material of dielectric constant $K$. The remaining half contains air. The capacitor is now given a charge $Q$. Then:

An air-filled parallel plate capacitor has capacity $C$. If the distance between the plates is doubled and it is immersed in a liquid,the capacity becomes twice. The dielectric constant of the liquid is:

The plates of a parallel plate capacitor are charged up to $100 \,V$. $A$ $2 \,mm$ thick insulator sheet is inserted between the plates. Then, to maintain the same potential difference, the distance between the plates is increased by $1.6 \,mm$. The dielectric constant of the insulator is

When the air between the plates of a charged parallel plate capacitor is replaced by a dielectric medium,the intensity of the electric field:

$A$ parallel plate capacitor with air between the plates has a capacitance $C$. If the distance between the plates is doubled and the space between the plates is filled with a dielectric of dielectric constant $6$,then the capacitance will become

Vedclass Test Series

Exam Paper Generator

Online Exam Module