The distance between the poles of a horse sho | vedclass

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(C) The net magnetic field at the midpoint $P$ is the vector sum of the magnetic fields due to the North pole $(N)$ and the South pole $(S)$.Since the

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$8 	imes 10^{-7}\, T$

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(C) The net magnetic field at the midpoint $P$ is the vector sum of the magnetic fields due to the North pole $(N)$ and the South pole $(S)$.Since the point $P$ is midway between the poles,the distance $r$ from each pole to $P$ is $r = \frac{0.1\, m}{2} = 0.05\, m$.The magnetic field due to a single pole of strength $m$ at a distance $r$ is given by $B = \frac{\mu_0}{4\pi} \frac{m}{r^2}$.Here,$\frac{\mu_0}{4\pi} = 10^{-7}\, T\cdot m/A$.Thus,the magnetic field due to the $N$-pole is $B_N = 10^{-7} 	imes \frac{0.01}{(0.05)^2} = 10^{-7} 	imes \frac{0.01}{0.0025} = 4 	imes 10^{-7}\, T$.Similarly,the magnetic field due to the $S$-pole is $B_S = 10^{-7} 	imes \frac{0.01}{(0.05)^2} = 4 	imes 10^{-7}\, T$.Since both fields point in the same direction (from $N$ to $S$),the net magnetic field is $B_{net} = B_N + B_S = 4 	imes 10^{-7} + 4 	imes 10^{-7} = 8 	imes 10^{-7}\, T$.

The distance between the poles of a horse shoe magnet is $0.1\, m$ and its pole strength is $0.01\, A\cdot m$. The induction of magnetic field at a point midway between the poles will be

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