The distance between two charges 25,mu C and | vedclass

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Question

(A) Let the two charges be $Q_1 = 25\,\mu C$ and $Q_2 = 36\,\mu C$,separated by a distance $x = 11\,cm$.Let the point $N$ be at a distance $x_1$ from

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At a distance of $5\,cm$ from $25\,\mu C$

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(A) Let the two charges be $Q_1 = 25\,\mu C$ and $Q_2 = 36\,\mu C$,separated by a distance $x = 11\,cm$.Let the point $N$ be at a distance $x_1$ from $Q_1$ where the electric field intensity is zero.At point $N$,the magnitude of the electric field due to $Q_1$ $(E_1)$ must be equal to the magnitude of the electric field due to $Q_2$ $(E_2)$.$|E_1| = |E_2|$$\frac{k Q_1}{x_1^2} = \frac{k Q_2}{(x - x_1)^2}$Taking the square root on both sides:$\frac{\sqrt{Q_1}}{x_1} = \frac{\sqrt{Q_2}}{x - x_1}$$x_1 = \frac{x \sqrt{Q_1}}{\sqrt{Q_1} + \sqrt{Q_2}}$Substituting the values:$x_1 = \frac{11 	imes \sqrt{25}}{\sqrt{25} + \sqrt{36}} = \frac{11 	imes 5}{5 + 6} = \frac{55}{11} = 5\,cm$.Thus,the electric field is zero at a distance of $5\,cm$ from the $25\,\mu C$ charge.

The distance between two charges $25\,\mu C$ and $36\,\mu C$ is $11\,cm$. At what point on the line joining the two charges will the electric field intensity be zero?

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