(D) The distance $d$ between two parallel lines $ax + by + c_1 = 0$ and $ax + by + c_2 = 0$ is given by the formula $d = \frac{|c_1 - c_2|}{\sqrt{a^2

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(D) The distance $d$ between two parallel lines $ax + by + c_1 = 0$ and $ax + by + c_2 = 0$ is given by the formula $d = \frac{|c_1 - c_2|}{\sqrt{a^2 + b^2}}$.Here,$a = 3$,$b = 4$,$c_1 = -8$,and $c_2 = -3$.Substituting these values into the formula:$d = \frac{|-8 - (-3)|}{\sqrt{3^2 + 4^2}}$$d = \frac{|-8 + 3|}{\sqrt{9 + 16}}$$d = \frac{|-5|}{\sqrt{25}}$$d = \frac{5}{5} = 1$.Thus,the distance between the lines is $1$ unit.

Class 11 Mathematics Straight Lines Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

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The distance between two parallel lines $3x + 4y - 8 = 0$ and $3x + 4y - 3 = 0$ is given by

A
$4$
B
$5$
C
$3$
D
$1$

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Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

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DifficultJEE MAIN 2022

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$A$ line has slope $m$ and $y$-intercept $4$. The distance between the origin and the line is equal to

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MediumTS EAMCET 2017

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The perpendicular distance from the point $(1, \pi)$ to the line joining $(1, 0^{\circ})$ and $(1, \frac{\pi}{2})$ (in polar coordinates) is

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The distance between two parallel lines $3x + 4y - 8 = 0$ and $3x + 4y - 3 = 0$ is given by

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