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(C) To find the mean,we first calculate the class marks $(x_i)$ for each interval.Number of wicketsNumber of bowlers $(f_i)$Class mark $(x_i)$$f_i x_i

Vedclass · Accepted Answer

$152.89$

Vedclass · Answer

(C) To find the mean,we first calculate the class marks $(x_i)$ for each interval.Number of wicketsNumber of bowlers $(f_i)$Class mark $(x_i)$$f_i x_i$$20$-$60$$7$$40$$280$$60$-$100$$5$$80$$400$$100$-$150$$16$$125$$2000$$150$-$250$$12$$200$$2400$$250$-$350$$2$$300$$600$$350$-$450$$3$$400$$1200$Total$\sum f_i = 45$$\sum f_i x_i = 6880$The mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{6880}{45} \approx 152.89$.This mean signifies that,on average,the bowlers have taken $152.89$ wickets in the given one-day cricket matches.

Literacy rate (in $\%$)	$45-55$	$55-65$	$65-75$	$75-85$	$85-95$
Number of cities	$3$	$10$	$11$	$8$	$3$

Marks	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Number of students	$2$	$4$	$7$	$6$	$1$

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Calculate the mean of the scores of $20$ students in a mathematics test:

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Number of wickets	$20$-$60$	$60$-$100$	$100$-$150$	$150$-$250$	$250$-$350$	$350$-$450$
Number of bowlers	$7$	$5$	$16$	$12$	$2$	$3$