The effective capacitances of two capacitors are $3\,\mu F$ and $16\,\mu F$,when they are connected in series and parallel respectively. The capacitances of the two capacitors are:

Consider the combination of $2$ capacitors $C_{1}$ and $C_{2}$,with $C_{2} > C_{1}$. When connected in parallel,the equivalent capacitance is $\frac{15}{4}$ times the equivalent capacitance of the same capacitors connected in series. Calculate the ratio of the capacitors,$\frac{C_{2}}{C_{1}}$.

Find the equivalent capacitance across $A$ and $B$ in $\mu F$.

Two capacitors of capacity $4 \mu F$ and $6 \mu F$ are connected in series to a $500 \ V$ battery. The potential difference across the $4 \mu F$ capacitor is: (in $V$)

The equivalent capacitance of three capacitors of capacitance $C_1, C_2$ and $C_3$ connected in parallel is $12$ units and their product is $C_1 \cdot C_2 \cdot C_3 = 48$. When the capacitors $C_1$ and $C_2$ are connected in parallel,the equivalent capacitance is $6$ units. Then the capacitances are:

What is the effective capacitance between points $X$ and $Y$ in $\mu F$?