The electric current i in the circuit shown i | vedclass

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(D) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$:The inc

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$4$

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(D) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$:The incoming currents are $3 \ A$ and $2 \ A$. Let the current flowing from $A$ to $B$ be $i_1$.$i_1 = 3 \ A + 2 \ A = 5 \ A$.At junction $B$:The incoming current is $i_1 = 5 \ A$. The outgoing currents are $2 \ A$ and the current flowing from $B$ to $C$,let it be $i_2$.$i_1 = 2 \ A + i_2 \implies 5 \ A = 2 \ A + i_2 \implies i_2 = 3 \ A$.At junction $C$:The incoming currents are $i_2 = 3 \ A$ and $1 \ A$. The outgoing current is $i$.$i = i_2 + 1 \ A = 3 \ A + 1 \ A = 4 \ A$.Therefore,the value of current $i$ is $4 \ A$.

The electric current $i$ in the circuit shown is (in $A$)

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