The electric field in the region is vec{E} = | vedclass

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(D) The electric field is given by $\vec{E} = a\hat{i} + b\hat{j}$.Since the square area of side $l$ is parallel to the $Y-Z$ plane, its area vector $

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$al^2$

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(D) The electric field is given by $\vec{E} = a\hat{i} + b\hat{j}$.Since the square area of side $l$ is parallel to the $Y-Z$ plane, its area vector $\vec{A}$ is directed along the $X$-axis.Thus, the area vector is $\vec{A} = l^2 \hat{i}$.The electric flux $\phi$ is defined as the dot product of the electric field and the area vector:$\phi = \vec{E} \cdot \vec{A}$$\phi = (a\hat{i} + b\hat{j}) \cdot (l^2 \hat{i})$$\phi = a \cdot l^2 (\hat{i} \cdot \hat{i}) + b \cdot l^2 (\hat{j} \cdot \hat{i})$Since $\hat{i} \cdot \hat{i} = 1$ and $\hat{j} \cdot \hat{i} = 0$, we get:$\phi = al^2$.

The electric field in the region is $\vec{E} = a\hat{i} + b\hat{j}$ where $a$ and $b$ are constants. The net electric flux passing through a square area of side $l$ parallel to the $Y-Z$ plane is

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