The electric field of an electromagnetic wave | vedclass

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(C) The general equation for a wave is given by $E = E_0 \sin(\omega t - kx)$.Comparing this with the given equation $\overline{E}(x,t) = 25 \sin(2.0

Vedclass · Accepted Answer

$1.5$

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(C) The general equation for a wave is given by $E = E_0 \sin(\omega t - kx)$.Comparing this with the given equation $\overline{E}(x,t) = 25 \sin(2.0 	imes 10^{15}t - 10^{7}x)\hat{n}$, we get:$\omega = 2.0 	imes 10^{15} 	ext{ rad/s}$$k = 10^{7} 	ext{ m}^{-1}$The velocity of the wave in the medium is $v = \frac{\omega}{k}$.$v = \frac{2.0 	imes 10^{15}}{10^7} = 2.0 	imes 10^8 	ext{ m/s}$.The refractive index $\mu$ is given by $\mu = \frac{c}{v}$, where $c = 3 	imes 10^8 	ext{ m/s}$ is the speed of light in vacuum.$\mu = \frac{3 	imes 10^8}{2 	imes 10^8} = 1.5$.

The electric field of an electromagnetic wave travelling through a medium is given by $\overline{E}(x,t) = 25 \sin(2.0 \times 10^{15}t - 10^{7}x)\hat{n}$. The refractive index of the medium is . . . . . . . (All given measurements are in $SI$ units)

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