The electric field part of an electromagnetic wave in a medium is represented by $E_x = 0$; $E_y = 2.5 \frac{N}{C} \cos \left[ (2\pi \times 10^6 \frac{rad}{s})t - (\pi \times 10^{-2} \frac{rad}{m})x \right]$; $E_z = 0$. The wave is:
- AMoving along $-x$ direction with frequency $10^6 \, Hz$ and wavelength $200 \, m$.
- BMoving along $y$ direction with frequency $2\pi \times 10^6 \, Hz$ and wavelength $200 \, m$.
- CMoving along $x$ direction with frequency $10^6 \, Hz$ and wavelength $100 \, m$.
- DMoving along $x$ direction with frequency $10^6 \, Hz$ and wavelength $200 \, m$.
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Similar Questions
The speed of an electromagnetic wave in a medium (whose dielectric constant is $2.25$ and relative permeability is $4$) is equal to .......... $\times 10^8 \, m/s$.
Easy
View SolutionThis question has Statement-$1$ and Statement-$2$. Of the four choices given after the statements,choose the one that best describes the two statements.
Statement-$1$: Out of radio waves and microwaves,the radio waves undergo more diffraction.
Statement-$2$: Radio waves have a greater frequency compared to microwaves.
Statement-$1$: Out of radio waves and microwaves,the radio waves undergo more diffraction.
Statement-$2$: Radio waves have a greater frequency compared to microwaves.
$A$ plane electromagnetic wave is travelling in the positive $X$-axis. At the instant shown,the electric field at the extremely narrow dashed rectangle is in the $-ve$ $Z$-direction and its magnitude is increasing. Which diagram correctly shows the direction and relative magnitudes of the magnetic field at the edges of the rectangle?
Medium
View SolutionIf the peak value of the magnetic field of an electromagnetic wave is $30 \times 10^{-9} \ T$,then the peak value of the electric field is (in $Vm^{-1}$)
The electric field and magnetic field components of an electromagnetic wave going through vacuum are described by
$E_x = E_0 \sin(kz - \omega t)$
$B_y = B_0 \sin(kz - \omega t)$
Then the correct relation between $E_0$ and $B_0$ is given by
$E_x = E_0 \sin(kz - \omega t)$
$B_y = B_0 \sin(kz - \omega t)$
Then the correct relation between $E_0$ and $B_0$ is given by
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