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(C) According to Gauss's Law,the total electric flux $\phi_E$ through any closed surface is equal to the net charge $q_{enclosed}$ enclosed by the sur

Vedclass · Accepted Answer

the same for all the figures

Vedclass · Answer

(C) According to Gauss's Law,the total electric flux $\phi_E$ through any closed surface is equal to the net charge $q_{enclosed}$ enclosed by the surface divided by the permittivity of free space $\epsilon_0$.Mathematically,$\phi_E = \frac{q_{enclosed}}{\epsilon_0}$.In all four figures $(a)$,$(b)$,$(c)$,and $(d)$,the charge enclosed by the surface is the same,which is $+q$.Since the enclosed charge is identical for all surfaces and $\epsilon_0$ is a constant,the electric flux $\phi_E$ through each surface must be equal.Therefore,the electric flux is the same for all the figures.

The electric flux through the surface in the given figures is:

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