The electric force acting between two point c | vedclass

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Question

(D) The electric force between two point charges in vacuum is given by $F_{	ext{air}} = \frac{1}{4\pi\epsilon_0} \frac{q_1q_2}{r^2} = 16 \ N$.When th

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(D) The electric force between two point charges in vacuum is given by $F_{	ext{air}} = \frac{1}{4\pi\epsilon_0} \frac{q_1q_2}{r^2} = 16 \ N$.When the same charges are placed in a medium with dielectric constant $K$,the force is given by $F_{	ext{medium}} = \frac{F_{	ext{air}}}{K}$.Given $F_{	ext{air}} = 16 \ N$ and $K = 8$.Therefore,$F_{	ext{medium}} = \frac{16}{8} = 2 \ N$.Thus,the correct option is $D$.

The electric force acting between two point charges kept at a certain distance in vacuum is $16 \ N$. If the same two charges are kept at the same distance in a medium of dielectric constant $8$,the electric force acting between them is . . . . . . .

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