The electric potential at the surface of an a | vedclass

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Question

(D) The electric potential $V$ at the surface of a nucleus is given by the formula: $V = \frac{kQ}{R}$,where $k = 9 	imes 10^9 	ext{ N m}^2/	ext{C}

Vedclass · Accepted Answer

$8$

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(D) The electric potential $V$ at the surface of a nucleus is given by the formula: $V = \frac{kQ}{R}$,where $k = 9 	imes 10^9 	ext{ N m}^2/	ext{C}^2$,$Q = Ze$,and $R$ is the radius.Given: $Z = 50$,$e = 1.6 	imes 10^{-19} 	ext{ C}$,and $R = 9 	imes 10^{-13} 	ext{ cm} = 9 	imes 10^{-15} 	ext{ m}$.Substituting the values:$V = \frac{(9 	imes 10^9) 	imes (50 	imes 1.6 	imes 10^{-19})}{9 	imes 10^{-15}}$$V = \frac{9 	imes 10^9 	imes 80 	imes 10^{-19}}{9 	imes 10^{-15}}$$V = 80 	imes 10^{-10} 	imes 10^{15} 	ext{ V}$$V = 80 	imes 10^5 	ext{ V} = 8 	imes 10^6 	ext{ V}$.Thus,the potential is $8 	imes 10^6 	ext{ V}$.

The electric potential at the surface of an atomic nucleus $(Z=50)$ of radius $9 \times 10^{-13} \text{ cm}$ is . . . . . . $\times 10^6 \text{ V}$.

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