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(D) Electric potential on the surface of the sphere is given by $V = k \frac{Q}{R}$,where $k = 9 	imes 10^9 \,N \cdot m^2/C^2$.Given $V = 200 \,V$ an

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$166.7$

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(D) Electric potential on the surface of the sphere is given by $V = k \frac{Q}{R}$,where $k = 9 	imes 10^9 \,N \cdot m^2/C^2$.Given $V = 200 \,V$ and $R = 5 \,cm = 0.05 \,m$.$200 = 9 	imes 10^9 	imes \frac{Q}{0.05} \implies Q = \frac{200 	imes 0.05}{9 	imes 10^9} = \frac{10}{9} 	imes 10^{-9} \,C$.The potential at a distance $r$ from the centre of the sphere is $V(r) = k \frac{Q}{r}$.Potential at point $A$ $(r_A = 15 \,cm = 0.15 \,m)$: $V_A = 9 	imes 10^9 	imes \frac{Q}{0.15} = \frac{9 	imes 10^9}{0.15} 	imes \frac{10}{9} 	imes 10^{-9} = \frac{10}{0.15} = 66.67 \,V$.Potential at point $B$ $(r_B = 10 \,cm = 0.10 \,m)$: $V_B = 9 	imes 10^9 	imes \frac{Q}{0.10} = \frac{9 	imes 10^9}{0.10} 	imes \frac{10}{9} 	imes 10^{-9} = \frac{10}{0.10} = 100 \,V$.Work done in moving a charge $q = 5 \,C$ from $A$ to $B$ is $W = q(V_B - V_A)$.$W = 5 	imes (100 - 66.67) = 5 	imes 33.33 = 166.65 \,J \approx 166.7 \,J$.

The electric potential on the surface of a charged spherical conductor of radius $5 \,cm$ is $200 \,V$. The work done in moving a charge of $+5 \,C$ from a point $A$ to another point $B$ situated at distances of $15 \,cm$ and $10 \,cm$ respectively from the centre of the sphere is (in $\,J$)

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