The electrode potentials for Cu^{2+}_{(aq)} + | vedclass

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(B) Given:$(1) \ Cu^{2+}_{(aq)} + e^- 	o Cu^{+}_{(aq)}$; $\Delta G_1 = -1 	imes 0.15 	imes F$$(2) \ Cu^{+}_{(aq)} + e^- 	o Cu_{(s)}$; $\Delta G_2

Vedclass · Accepted Answer

$0.325$

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(B) Given:$(1) \ Cu^{2+}_{(aq)} + e^- 	o Cu^{+}_{(aq)}$; $\Delta G_1 = -1 	imes 0.15 	imes F$$(2) \ Cu^{+}_{(aq)} + e^- 	o Cu_{(s)}$; $\Delta G_2 = -1 	imes 0.50 	imes F$We need to find $E^\circ$ for the reaction:$(3) \ Cu^{2+}_{(aq)} + 2e^- 	o Cu_{(s)}$; $\Delta G_3 = -2 	imes F 	imes E^\circ_3$Since reaction $(3) = (1) + (2)$,we have:$\Delta G_3 = \Delta G_1 + \Delta G_2$$-2 	imes F 	imes E^\circ_3 = (-1 	imes 0.15 	imes F) + (-1 	imes 0.50 	imes F)$$-2 	imes E^\circ_3 = -0.15 - 0.50$$-2 	imes E^\circ_3 = -0.65$$E^\circ_3 = \frac{0.65}{2} = 0.325 \ V$

The electrode potentials for $Cu^{2+}_{(aq)} + e^- \to Cu^{+}_{(aq)}$ and $Cu^{+}_{(aq)} + e^- \to Cu_{(s)}$ are $+0.15 \ V$ and $+0.50 \ V$ respectively. The value of $E^\circ$ for the reaction $Cu^{2+}_{(aq)} + 2e^- \to Cu_{(s)}$ will be ............ $V$.

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