The electron affinity values are negative for:
$A$. $Be \rightarrow Be^{-}$
$B$. $N \rightarrow N^{-}$
$C$. $O^{-} \rightarrow O^{2-}$
$D$. $Na \rightarrow Na^{-}$
$E$. $Al \rightarrow Al^{-}$
Choose the most appropriate answer from the options given below:

  • A
    $D$ and $E$ only
  • B
    $A, B, D$ and $E$ only
  • C
    $A$ and $D$ only
  • D
    $A, B$ and $C$ only

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Which of the following has the highest electron affinity?

Among the following options, the correct trend in the electron gain enthalpy is

Which element in each of the following pairs has a more negative electron gain enthalpy?
$(i)$ $O$ or $F$ $(ii)$ $F$ or $Cl$

Explain the following :
$(1)$ $Pb^{4+}$ acts as an oxidizing agent but $Sn^{2+}$ acts as a reducing agent.
$(2)$ Electron gain enthalpy of chlorine is more negative as compared to fluorine.

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Consider the following conversions:
$(i) \, O_{(g)} + e^- \to O_{(g)}^{-}, \Delta H_1$
$(ii) \, F_{(g)} + e^- \to F_{(g)}^{-}, \Delta H_2$
$(iii) \, Cl_{(g)} + e^- \to Cl_{(g)}^{-}, \Delta H_3$
$(iv) \, O_{(g)}^{-} + e^- \to O_{(g)}^{2-}, \Delta H_4$
Based on the given information,which statement is incorrect?

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