The electron configuration of Fe^{3+} is (ato | vedclass

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(C) The atomic number of $Fe$ is $26$. The ground state electronic configuration of a neutral $Fe$ atom is $[Ar] 3d^6 4s^2$.To form the $Fe^{3+}$ ion,

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$[Ar] 3d^5 4s^0$

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(C) The atomic number of $Fe$ is $26$. The ground state electronic configuration of a neutral $Fe$ atom is $[Ar] 3d^6 4s^2$.To form the $Fe^{3+}$ ion,we must remove $3$ electrons from the neutral atom.Electrons are removed from the outermost shell first,which is the $4s$ orbital,followed by the $3d$ orbital.Removing $2$ electrons from $4s$ and $1$ electron from $3d$ results in the configuration: $[Ar] 3d^5 4s^0$.

The electron configuration of $Fe^{3+}$ is (atomic number of $Fe = 26$)

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