The electron distribution in d^{n} coordinati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In coordination complexes,the electron distribution is determined by the competition between the crystal field splitting energy $(\Delta_{0})$ and

Vedclass · Accepted Answer

$\Delta_{0} < P$

Vedclass · Answer

(B) In coordination complexes,the electron distribution is determined by the competition between the crystal field splitting energy $(\Delta_{0})$ and the pairing energy $(P).$If $\Delta_{0} > P$,the energy required to pair electrons is less than the energy required to promote an electron to the higher energy $e_{g}$ orbitals. This leads to the formation of low spin complexes.If $\Delta_{0} Therefore,the condition that favours the formation of high spin complexes is $\Delta_{0} < P$.

The electron distribution in $d^{n}$ coordination complexes depends on the magnitude of crystal field splitting,$(\Delta_{0})$ and pairing energy $(P).$ The condition which favours the formation of high spin complexes is

Similar Questions

Which of the following ligands has the highest field strength?

The electronic spectrum of $[Ti(H_2O)_6]^{3+}$ gives a single broad peak with a maxima at $20300 \, cm^{-1}$. The crystal field stabilization energy is equal to .......... $kJ \, mol^{-1}$

What is the electronic arrangement of a metal atom/ion in an octahedral complex with a $d^4$ configuration,if $\Delta_o < \text{pairing energy}$?

Why are low spin tetrahedral complexes not formed?

Identify the correct increasing order of field strength of ligands from the following.

Vedclass Test Series

Exam Paper Generator

Online Exam Module