The electronegativity difference between N an | vedclass

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(C) The electronegativity of $N$ $(3.04)$ is greater than that of $H$ $(2.20)$,so the bond dipoles $(N-H)$ and the lone pair dipole on $N$ point in th

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in $NH_3$ the atomic dipole and bond dipole are in the same direction whereas in $NF_3$ these are in opposite directions

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(C) The electronegativity of $N$ $(3.04)$ is greater than that of $H$ $(2.20)$,so the bond dipoles $(N-H)$ and the lone pair dipole on $N$ point in the same direction,reinforcing each other.In $NF_3$,the electronegativity of $F$ $(3.98)$ is greater than that of $N$ $(3.04)$,so the bond dipoles $(N-F)$ point away from $N$,which is opposite to the direction of the lone pair dipole on $N$. This causes the bond dipoles to partially cancel the lone pair dipole,resulting in a much smaller net dipole moment.

The electronegativity difference between $N$ and $F$ is greater than that between $N$ and $H$,yet the dipole moment of $NH_3$ $(1.5 \ D)$ is larger than that of $NF_3$ $(0.2 \ D)$. This is because

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