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(A) The given electronic configuration $1s^2, 2s^2 2p^6, 3s^2 3p^3$ corresponds to the element Phosphorus $(P)$ with an atomic number of $15$.Phosphor

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(A) The given electronic configuration $1s^2, 2s^2 2p^6, 3s^2 3p^3$ corresponds to the element Phosphorus $(P)$ with an atomic number of $15$.Phosphorus belongs to Group $15$ of the periodic table.The element located immediately below Phosphorus in Group $15$ is Arsenic $(As)$.To find the atomic number of the element below,we add the magic number $18$ to the atomic number of Phosphorus $(15 + 18 = 33)$.Thus,the atomic number of Arsenic is $33$.

The electronic configuration of an element is $1s^2, 2s^2 2p^6, 3s^2 3p^3$. What is the atomic number of the element which is just below the above element in the periodic table?

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