The electronic configuration of an element with the largest difference between the $1^{st}$ and $2^{nd}$ ionisation energies is

  • A
    $1s^{2} 2s^{2} 2p^{6}$
  • B
    $1s^{2} 2s^{2} 2p^{6} 3s^{1}$
  • C
    $1s^{2} 2s^{2} 2p^{6} 3s^{2}$
  • D
    $1s^{2} 2s^{2} 2p^{1}$

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Match the following List-$I$ and List-$II$ and select the correct answer using the codes given below.
List-$I$ (Successive Ionization Enthalpy) $\left( kJ \, mol^{-1} \right)$ List-$II$
Element$IE_1$$IE_2$$IE_3$CodeElement
$1$$2080$$3963$$6130$$(a)$$H$
$2$$520$$7297$$11810$$(b)$$Li$
$3$$900$$1758$$14810$$(c)$$Be$
$4$$800$$2428$$3660$$(d)$$B$
----$(e)$$Ne$

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A:$ The energy required to form $Mg^{2+}$ from $Mg$ is much higher than that required to produce $Mg^{+}$.
Reason $R:$ $Mg^{2+}$ is a small ion and carries more charge than $Mg^{+}$.
In the light of the above statements,choose the correct answer from the options given below:

The first ionization potential values (in $eV$) for nitrogen and oxygen atoms are respectively:

Discuss and compare the trend in ionisation enthalpy of the elements of group-$1$ with those of group-$17$ elements.

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Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: The first ionization enthalpy of $O$ is lower than that of $N$ and $F$.
Reason $R$: The loss of an electron from $O$ leads to a stable half-filled $p$ orbital.
In light of the above statements, choose the most appropriate answer from the options given below:

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