The element _{90}Th^{232} belongs to the thor | vedclass

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(A) The thorium series is a $4n$ radioactive decay series.The parent element of this series is $_{90}Th^{232}$,and it undergoes a series of $\alpha$ a

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$_{82}Pb^{208}$

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(A) The thorium series is a $4n$ radioactive decay series.The parent element of this series is $_{90}Th^{232}$,and it undergoes a series of $\alpha$ and $\beta$ decays to reach a stable end product.									$4n$ Series (Name)									Parent to End Element													$4n$: Thorium series			$4n+1$: Neptunium series			$4n+2$: Uranium series			$4n+3$: Actinium series									$_{90}Th^{232} \rightarrow _{82}Pb^{208}$			$_{94}Pu^{241} \rightarrow _{83}Bi^{209}$			$_{92}U^{238} \rightarrow _{82}Pb^{206}$			$_{92}U^{235} \rightarrow _{82}Pb^{207}$						Therefore,the end product of the thorium series is $_{82}Pb^{208}$.

The element $_{90}Th^{232}$ belongs to the thorium series. Which of the following will act as the end product of this series?

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