The empirical formula of a non-electrolyte is | vedclass

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(D) Since the solutions have the same osmotic pressure at the same temperature,their molar concentrations must be equal.Concentration of compound = Co

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$C_{4}H_{8}O_{4}$

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(D) Since the solutions have the same osmotic pressure at the same temperature,their molar concentrations must be equal.Concentration of compound = Concentration of glucose = $0.05 \ M$.Let $M$ be the molar mass of the compound. The concentration is given by $\frac{	ext{mass}}{M 	imes 	ext{Volume}}$. Assuming $1 \ L$ of solution,$\frac{6 \ g}{M} = 0.05 \ mol/L$.$M = \frac{6}{0.05} = 120 \ g/mol$.The empirical formula mass of $CH_{2}O = 12 + (2 	imes 1) + 16 = 30 \ g/mol$.The value of $n = \frac{	ext{Molecular mass}}{	ext{Empirical formula mass}} = \frac{120}{30} = 4$.Therefore,the molecular formula is $(CH_{2}O)_{4} = C_{4}H_{8}O_{4}$.

The empirical formula of a non-electrolyte is $CH_{2}O$. $A$ solution containing $6 \ g$ of the compound exerts the same osmotic pressure as that of $0.05 \ M$ glucose solution at the same temperature. The molecular formula of the compound is

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