The end product of the reactions isC_2H_5NH_2 | vedclass

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(B) The reaction sequence is as follows:$1$. $C_2H_5NH_2 + HNO_2 \rightarrow C_2H_5OH + N_2 + H_2O$ (Product $A$ is $C_2H_5OH$)$2$. $C_2H_5OH + PCl_5

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Ethyl amine

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(B) The reaction sequence is as follows:$1$. $C_2H_5NH_2 + HNO_2 \rightarrow C_2H_5OH + N_2 + H_2O$ (Product $A$ is $C_2H_5OH$)$2$. $C_2H_5OH + PCl_5 \rightarrow C_2H_5Cl + POCl_3 + HCl$ (Product $B$ is $C_2H_5Cl$)$3$. $C_2H_5Cl + NH_3 \rightarrow C_2H_5NH_2 + HCl$ (Product $C$ is $C_2H_5NH_2$)Thus,the end product $C$ is ethyl amine.

The end product of the reactions is
$C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3} C$

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The end product of the reactions is$C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3} C$