The ends of a stretched wire of length $L$ are fixed at $x = 0$ and $x = L$. In one experiment,the displacement of the wire is $y_1 = A \sin(\pi x/L) \sin(\omega t)$ and the energy is $E_1$. In another experiment,its displacement is $y_2 = A \sin(2\pi x/L) \sin(2\omega t)$ and the energy is $E_2$. Then:

  • A
    $E_2 = E_1$
  • B
    $E_2 = 2E_1$
  • C
    $E_2 = 4E_1$
  • D
    $E_2 = 16E_1$

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