The energy gap of silicon is 1.1 , eV. At wha | vedclass

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(A) The energy gap of silicon is given as $E_g = 1.1 \, eV$. To find the maximum wavelength $\lambda$ that can be absorbed,we use the relation $E_g =

Vedclass · Accepted Answer

$11272$

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(A) The energy gap of silicon is given as $E_g = 1.1 \, eV$. To find the maximum wavelength $\lambda$ that can be absorbed,we use the relation $E_g = \frac{hc}{\lambda}$. Substituting the values: $h = 6.63 	imes 10^{-34} \, J \cdot s$,$c = 3 	imes 10^8 \, m/s$,and $1 \, eV = 1.6 	imes 10^{-19} \, J$. $\lambda = \frac{hc}{E_g} = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}{1.1 	imes 1.6 	imes 10^{-19}} \, m$. $\lambda \approx 1.13 	imes 10^{-6} \, m = 11272 \, \mathring A$. Photons with wavelengths longer than this will not have enough energy to excite electrons across the band gap.

The energy gap of silicon is $1.1 \, eV$. At what wavelength will silicon stop absorbing photons? (in $\mathring A$)

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